The total flux associated with given cube will be, where ′a′ is side of cube :– (1ϵo=4π×9×109)
A
162π×10−3Nm2C
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B
162π×103Nm2C
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C
162π×10−6Nm2C
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D
162π×106Nm2C
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Solution
The correct option is B162π×103Nm2C
Total flux through the cube due to any one charge is18th of the total flux generated, as it can be imagined that the charge is at the centre of the bigger cube of which this cube is 18th part. So, ϕtotal=18(1+2+3+4+5+6+7+8)ϵoμC =162π×103Nm2C