The total height of 10 identical coins each of thickness 0.5 cm placed one over the other is 50 mm.

True

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False

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Solution

The correct option is A True
Thickness of each coin $t = 0.5 c m$
Number of coins $N = 10$
So, total height $h = N t = 10 \times 0.5 c m = 5 c m$
We know that $1 c m = 10 m m$
Thus $h = 5 c m \times \frac{10 m m}{1 c m} = 50 m m$

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The total height of 10 identical coins each of thickness 0.5 cm placed one over the other is 50 mm.

The correct option is A TrueThickness of each coin t=0.5 cmNumber of coins N=10So, total height h=Nt=10×0.5 cm=5 cmWe know that 1 cm=10 mmThus h=5 cm×10 mm1 cm=50 mm

The correct option is A True
Thickness of each coin $t = 0.5 c m$
Number of coins $N = 10$
So, total height $h = N t = 10 \times 0.5 c m = 5 c m$
We know that $1 c m = 10 m m$
Thus $h = 5 c m \times \frac{10 m m}{1 c m} = 50 m m$