Question

The total kinetic energy (in joules) of the molecules in $8g$ of methane at ${27}^{o}C$ is:

• A. $374100J$
• B. $935.3J$
• C. $1870.65J$
• D. $700J$

Answer 1

Answer: (C)

$1870.65J$

$KE=\frac{3}{2}nRT$

8gm of $C{H}_4=\frac{8}{16}=0.5mol$

$\therefore$ KE of 8gm of $C{H}_4$ at ${27}^{\circ }C=\frac{3}{2}\times 0.5\times 8.314\times 300=1870.65J$