Question

The total kinetic energy of $8$ litres of helium molecules at $5$ atmosphere pressure will be

• A. $607Joules$
• B. $6078Joules$
• C. $607ergs$
• D. $6078ergs$

Answer 1

Answer: (B)

$6078Joules$

Given data,

$PressureP=5$

$VolumeV=8$

$1atmosphere=1.013\times {10}^{5}pascal$

$K.E.=?$

We have the kinetic energy as
$K.E.=\frac{3}{2}PV$

$=\frac{3}{2}\times 5\times 1.01325\times {10}^5\times 8\times {10}^{-3}=6078J$