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Question

The total length of a runway is 1000 m. The elevation at an interval of 100 m is as follows :
Distance(m) 100 200 300 400 500 600 700 800 900 1000
Elevation(m) 100 99.2 98.6 99.2 101.4 97.6 100 101.6 102.4 101

The effective gradient of the runway (in %, round off to two decimals) will be____
  1. 0.48

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Solution

The correct option is A 0.48
Effective gradient =

[Maximun,difference,in,elevationTotal,runway,length×100]

=[(102.497.6)1000×100]

= 0.48 %

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