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Standard XII

Chemistry

Electrolytes

The total mol...

Question

The total molar concentration of ions in $0.47$ M solution of $N a_{2} S O_{4}$ assuming its complete ionisation is:

1.88

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0.94

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1.43

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0.47

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Solution

The correct option is C $1.43$ M
$N a_{2} S O_{4} \to 2 N a^{+} + S O_{4}^{2 -}$
$0.47 M$ $2 \times 0.47$ $0.47$
$∴$ Total molar concentrations of ions
$= (2 \times 0.47) + 0.47$
$= 0.94 + 0.47$
$= 1.43 M$

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The total molar concentration of ions in 0.47 M solution of Na2SO4 assuming its complete ionisation is:

The correct option is C 1.43 MNa2SO4→2Na++SO2−40.47M 2×0.47 0.47∴ Total molar concentrations of ions=(2×0.47)+0.47=0.94+0.47=1.43M

The total molar concentration of ions in $0.47$ M solution of $N a_{2} S O_{4}$ assuming its complete ionisation is:

The correct option is C $1.43$ M
$N a_{2} S O_{4} \to 2 N a^{+} + S O_{4}^{2 -}$
$0.47 M$ $2 \times 0.47$ $0.47$
$∴$ Total molar concentrations of ions
$= (2 \times 0.47) + 0.47$
$= 0.94 + 0.47$
$= 1.43 M$