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Question

The total number of three digit numbers, the sum of whose digits is even, is equal to


A

450

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B

350

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C

250

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D

325

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Solution

The correct option is A

450


Explanation of the correct option.

Let n=pqr be the three digit number

So the sum of digits is =p+q+r

Given the the sum of the digits is even, that is p+q+r is even, then

Case

Number of ways

1

p,q,r all even

4×5×5=100 ways

2

p even and q,r are odd

4×5×5=100 ways

3

p odd and q,r are even

5×5×5=125 ways

4

q even and p,r are odd

5×5×5=125 ways

Therefore, total number of ways=100+100+125+125

=450

Hence,optionA is the correct option.


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