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Question

The total number of 9 digit numbers which have all different digits is

A
9!×2!
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B
10!
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C
9×9!
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D
None of the above
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Solution

The correct option is C 9×9!
The number is to be of 9 digits.

The first place can be filled in 9 ways only (as 0 can not be in the left most position )

Having filled up the first place the remaining 8 places can be filled in 9×8×7×...×2=9! ways

Hence, total number of 9 digit numbers with distinct digits is 9×9!

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