The total number of all possible isomeric ketones of molecular weight 100 and molecular formula (C6H12O) is/are:
A
5
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B
4
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C
3
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D
6
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Solution
The correct option is D 6 For a compound with molecular formula CcHhXxNnOo Degree of unsaturation=(c+1)−h2−x2+n2 Where, X = Halogen c=number of carbon atom h=number of hydrogen atom n=number of nitrogen atom o=number of oxygen atom In C6H12O Degree of unsaturation=(6+1)−122=1 The possible ketones (molecular formula =C6H12O) are 6