The total number of all possible isomeric ketones of molecular weight 100 and molecular formula (C6H12O) is/are:
A
5
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B
4
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C
3
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D
6
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Solution
The correct option is D 6 For a compound with molecular formula CcHhXxNnOo Degree of unsaturation=(c+1)−h2−x2+n2
Where, X = Halogen
c=number of carbon atom
h=number of hydrogen atom
n=number of nitrogen atom
o=number of oxygen atom
In C6H12O Degree of unsaturation=(6+1)−122=1
The possible ketones (molecular formula =C6H12O) are 6