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Byju's Answer
Standard VII
Chemistry
Sub-Atomic Particles
The total num...
Question
The total number of
α
- and
β
- particles given out during nuclear transformation is :
238
92
U
⟶
214
82
Pb
A
2
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B
4
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C
6
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D
8
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Solution
The correct option is
A
8
Balance reaction is
238
92
U
⟶
214
82
Pb
+
m
4
2
He
+
n
0
−
1
e
238
=
214
+
4
m
;
m
=
6
and
n
=
2
T
o
t
a
l
=
8
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Similar questions
Q.
Choose the correct numbers of
α
- and
β
-particles given out during nuclear transformation as :
238
92
U
→
214
82
Pb
Q.
The number of
α
and
β
particles emitted during the transformation of
90
T
h
232
to
82
P
b
208
are respectively :
Q.
The number of
α
and
β
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90
T
h
232
to
82
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208
are respectively
Q.
The number of
α
and
β
- particles emitted, when the following nuclear transformation takes place are x and y respectively.
Determine the value of x and y.
238
92
X
⟶
206
82
Y
.
Q.
The number of
α
and
β
-particles emitted during the transformation of
90
T
h
232
to
82
P
208
are respectively
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