Question

The total number of $\angle FIF$ angles in $I{F}_7$ having the bond angle value of ${90}^o$ is _______.

Answer 1

The central iodine atom in $I{F}_7$ undergoes $s{p}^3{d}^3$ hybridization which results in pentagonal bipyramidal geometry.

Each axial F atom forms five ${90}^o$ angles with five equatorial F atoms.

Hence, the total number of $\angle FIF$ angles in $I{F}_7$ having the bond angle value of ${90}^o$ is $10.$