Question

The total number of antibonding electrons in $N_2$ and $O_2$ molecules respectively is:

• A. $6,8$
• B. $5,8$
• C. $4,8$
• D. $4,6$

Answer 1

The correct option is D $4,6$

The total number of antibonding electrons in N2 and O2 molecules is 4 and 6 respectively. Hence, the option D is the correct answer.
$N_2:\left(\sigma 1s{)}^2\right({\sigma }^{\ast }1s{)}^2\left(\sigma 2s{)}^2\right({\sigma }^{\ast }2s{)}^2\left(\sigma 2p_x{)}^2\right(\pi 2p_y{)}^2(\pi 2p_z{)}^2$
$O_2:\left(\sigma 1s{)}^2\right({\sigma }^{\ast }1s{)}^2\left(\sigma 2s{)}^2\right({\sigma }^{\ast }2s{)}^2\left(\sigma 2p_x{)}^2\right(\pi 2p_y{)}^2\left(\pi 2p_z{)}^2\right({\pi }^{\ast }2p_z{)}^1({\pi }^{\ast }2p_z{)}^1$