The total number of atoms of all elements present in 1 mole of ammonium dichromate is

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6X10²⁹

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114X10²³

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Solution

The correct option is D
114X10²³

$(N H_{4})_{2} C r_{2} O_{7}$

$N o . o f a t o m s$ = $N o . o f m o l e s \times N \times a t o m i c i t y$

= $1 \times 6.023 \times 10^{23} \times 19 = 114 \times 10^{23}$

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