Question

The total number of atoms of all elements present in $1$ mole of ammonium dichromate is:

• A. $14$
• B. $19$
• C. $6\times {10}^{29}$
• D. $114\times {10}^{23}$

Answer 1

The correct option is D $114\times {10}^{23}$

One molecule of ammonium dichromate, $(N{H}_4{)}_{2}C{r}_2{O}_7$ contains $19$ atoms.

Thus, one mole of ammonium dichromate will contain $19\times 6.02\times {10}^{23}=114\times {10}^{23}$ atoms.