The total number of atoms of all elements present in 1 mole of ammonium dichromate is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$6 \times 10^{29}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$114 \times 10^{23}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
$114 \times 10^{23}$

$(N H_{4})_{2} C r_{2} O_{7}$

$N o . o f a t o m s$ = $N o . o f m o l e s \times N \times a t o m i c i t y$

= $1 \times 6.023 \times 10^{23} \times 19 = 114 \times 10^{23}$

Suggest Corrections

Similar questions

The total numbers of atoms all elements present in mole of ammonium dichromate is:

{K C l O}_{3}

Join BYJU'S Learning Program