The total number of bonding and antibonding electrons in $O {_{2}}^{+}$ are respectively. (If the answer is 14 and 7, then represent as 0147):

0105

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0205

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0104

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0202

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Solution

The correct option is A $0105$
From figure it can be seen that it has $10$ bonding electron and $5$ antibonding electron.

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