The total number of candidates who appeared for CS and ES together in 2011 were 25% more than the total number of candidates who appeared for the same together in 2010. How many female candidates appeared for both the exams together in 2011, if they formed $\frac{2}{5} t h$ of the total number of candidates appearing for both CS and ES that year?

52000

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58000

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60000

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62000

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64000

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Solution

The correct option is B 58000
Total number of candidates who appeared for CS and ES together in 2010 $= 76000 + 40000 = 116000$ .
So, the total number of candidates who appeared for CS and ES together in 2011 $= \frac{125}{100} \times 116000 = 145000$
Number of female candidates who appeared for both the exams together in 2011 = $\frac{2}{5} t h$ of the total number of candidates who appeared for both exams together in 2011 = $\frac{2}{5} \times 145000 = 58000$

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