The total number of candidates who appeared for CS and ES together in 2011 were 25% more than the total number of candidates who appeared for the same together in 2010. How many female candidates appeared for both the exams together in 2011, if they formed 25th of the total number of candidates appearing for both CS and ES that year?
Total number of candidates who appeared for CS and ES together in 2010 =76000+40000=116000.
So, the total number of candidates who appeared for CS and ES together in 2011 =125100×116000=145000
Number of female candidates who appeared for both the exams together in 2011 = 25th of the total number of candidates who appeared for both exams together in 2011 = 25×145000=58000