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Question

The total number of distinct xR for which x2x3xx24x29x21+x31+8x31+27x3=10 is

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Solution

xx21+x32x4x21+8x33x9x21+27x3=10

x3×det111+x3241+8x3391+27x3=10

x3×[4+108x3972x3254x3+3+24x3+6+6x3]=10

x3(12x3+2)=10

6x6+x35=0

6x6+6x35x35=0

(x3+1)(6x35)=0

x3=1,56, both of which have one real root
respectively.

Hence, total number of distinct values of x is 2.

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