Question

The total number of electrons present in $18$ ml of water is:

• A. $6.023\times {10}^{-24}$
• B. $6.023\times {10}^{24}$
• C. $6.023\times {10}^{23}$
• D. $12.023\times {10}^{24}$

Answer 1

The correct option is B $6.023\times {10}^{24}$

The total number of electrons present in $18$ ml of water is $6.023\times {10}^{24}$.
Number of electron in one molecule of $H_{2}O$ is $2+8=10$.
Density $=1g/ml$
$\therefore 18$ ml means $18$ g
Moles $=\frac{18}{18}=1$
Molecules $=6.023\times {10}^{23}$
Electrons $=6.023\times {10}^{23}\times 10=6.023\times {10}^{24}$