Question

# The total number of electrons present in $$18 \ mL$$ water (density $$1g/mL$$) is:

A
6.023×1023
B
6.023×1024
C
6.023×1025
D
6.023×1021

Solution

## The correct option is B $$6.023\times { 10 }^{ 24 }\quad$$Mass $$=18g$$       ($$\because m=v\times d$$)Number of molecules of $${H}_{2}O$$ in $$18g$$ mass$$\quad =6.023\times { 10 }^{ 23 }$$Number of electrons in $$18g$$ water$$=6.023\times { 10 }^{ 23 }\times 10$$ $$=6.023\times { 10 }^{ 24 }\quad$$Hence, the correct option is $$\text{B}$$Chemistry

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