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Question

The total number of electrons present in $$18 \ mL$$ water (density $$1g/mL$$) is:


A
6.023×1023
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B
6.023×1024
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C
6.023×1025
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D
6.023×1021
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Solution

The correct option is B $$6.023\times { 10 }^{ 24 }\quad $$
Mass $$=18g$$       ($$\because m=v\times d$$)

Number of molecules of $${H}_{2}O$$ in $$18g$$ mass

$$\quad =6.023\times { 10 }^{ 23 }$$

Number of electrons in $$18g$$ water

$$=6.023\times { 10 }^{ 23 }\times 10$$ 

$$=6.023\times { 10 }^{ 24 }\quad $$

Hence, the correct option is $$\text{B}$$

Chemistry

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