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Question

The total number of extremum point(s) for f(x)=x3+x2+x+1 is

A
0
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B
0.00
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C
0.0
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D
0.000
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Solution

Given, f(x)=x3+x2+x+1
f(x)=3x2+2x+1
D=412=8<0
Hence, f(x)>0 xR
So, There is no critical points for given f(x)
There is no possible point of local maxima/minima.

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