The total number of four-digit numbers xyzt such that x<y=z>t is
240
Given: x<y=z>t
First, lets fix y=z=9, then
8 possibilities(1 to 8) < 9 (fixed) > 9 possibilities(0 to 8), so total number of four-digit numbers =8×9=72
Similarly, 7 possibilities(1 to 7) < 8 (fixed) > 8 possibilities(0 to 7), so, total number of four-digit numbers =7×8=56
6 possibilities(1 to 6) < 7 (fixed) > 7 possibilities(0 to 6), so, total number of four-digit numbers =6×7=42
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Lastly, 1 possibility < 2 (fixed) > 2 possibilities, so, total number of four-digit numbers =1×2=2
⇒ Total numbers =72+56+42+30+20+12+6+2=240