CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The total number of geometrical isomers possible for [M(HO(CH2)2NH2)2Br2] is:


A
2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2

(HO(CH2)2NH2) is a bidentate ligand. The given complex has square bipyramidal shape. Its isomers are as shown.

1171762_1101266_ans_ad0c018b46a241fc87622c00fd40435a.JPG

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Substitution Reactions
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon