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Question

The total number of geometrical isomers possible in following compound is

A
2
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B
1
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C
6
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D
8
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Solution

The correct option is D 8
The given compound is a unsymmetrical compound. It has different terminal groups (methyl and phenyl).
The formula used to determine the number of geometrical isomers in compound having different terminal groups is, 2n, where n is the number of doube bond present in the molecule.
In the given compound we have 2 double bond and one ring with double bond. Double bond in ring doesnot show geometrical isomer so ring with double is equivalent to one double bond. Thus, n = 3
Therefore,
No. of geometrical isomers = 2n
= 23
= 8.

Hence, unsymmetrical compound with 2 double bonds and one doubly bonded ring has 8 stereoisomers.

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