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Question

The total number of injective mappings from a set with m elements to a set with n elements,mn, is

A
mn
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B
nm
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C
n!(nm)!
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D
n!
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Solution

The correct option is B n!(nm)!
Let A={a1,a2,a3.....am}
and B={b1,b2,b3.....bn} where mn
Given f:AB be an injective mapping.
So, for a1A, there are n possible choices for f(a1)B.
For a2A, there are (n1) possible choices for f(a2)B.
Similarly for amA, there are (nm1) choices for f(am)B
So, there are n(n1)(n2).....(nm1)=n!(nm)! injective mapping from A to B.

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