Question

The total number of lone pairs present in a water molecule is:

• A. 2

Answer 1

The correct option is A 2
<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> The pair of valence electrons that do not participate in bond formation is called lone pair.
In a water $\left({\text{H}}_2\text{O}\right)$molecule, oxygen is bonded to two hydrogen atoms.
Total number of valence electrons present in oxygen atom is 6.

It shares one electron with each hydrogen atom to form two single bonds.

Since, four valence electrons do not participate in any bond formation, there are two lone pairs in water molecule.