The total number of lone pairs present in XeF4 is
A) 10
B) 12
C) 14
D) 16

I did not understand the question because I know that there are only 2 lone pairs in XeF4. Can I please get the answer with an explanatation.
Thank you

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Solution

There are 3 lone pairs present on each F atom and two lone pairs present on Xe. So, the total number of lone pairs are : 4 X 3 + 2 = 14

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