The total number of men women and children working in a factory is 18. They earn Rs 4000 in a day. If the sum of the wages of all men all women and all children is in the ratio of 18 : 10 : 12 and if the wages of an individual man, woman and child is in the ratio 6 : 5 : 3, then how much a woman earns in a day?

400

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250

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150

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120

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Solution

The correct option is B 250
Ratio of number of men, women and children
$= \frac{18}{6} : \frac{10}{5} : \frac{12}{3} = 3 x : 2 x : 4 x$
$∴ (3 x + 2 x + 4 x) = 18$
$∴ x = 2$
Therefore, number of women = 4
Share of all women $= \frac{10}{40} \times 4000 = R s 1000 (∵ 18 + 10 + 12 = 40)$
$∴$ share of each woman $= \frac{1000}{4} = R s 250$

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The correct option is B 250Ratio of number of men, women and children =186:105:123=3x:2x:4x ∴(3x+2x+4x)=18 ∴x=2 Therefore, number of women = 4 Share of all women =1040×4000=Rs1000(∵18+10+12=40) ∴ share of each woman =10004=Rs 250