The total number of moles of chlorine gas evolved is:

0.5

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1.0

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2.0

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3.0

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Solution

The correct option is B $1.0$
Moles of $N a C l = 4 \times 0.5 = 2$ $m o l e s$
Moles of $C l^{-}$ ion $= 2$ $m o l e s$
$2 C l^{-} ⟶ C l_{2} + 2 e^{-}$
$2$ $m o l e s$
$1$ $m o l e$
So, $1$ $m o l e$ of $C l_{2}$ gas is evolved

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Similar questions

Q. A 4.0 molar aqueous solution of NaCl is prepared and 500 mL of this solution is electrolyzed. This leads to the evolution of chlorine gas at one of the electrode.

[Atomic mass: Na = 23, Hg = 200; 1 Faraday = 96500 coulombs]

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The total number of moles of chlorine gas evolved is:

The correct option is B 1.0Moles of NaCl=4×0.5=2 molesMoles of Cl− ion =2 moles2Cl−⟶Cl2+2e−2 moles 1 moleSo, 1 mole of Cl2 gas is evolved

The correct option is B $1.0$
Moles of $N a C l = 4 \times 0.5 = 2$ $m o l e s$
Moles of $C l^{-}$ ion $= 2$ $m o l e s$
$2 C l^{-} ⟶ C l_{2} + 2 e^{-}$
$2$ $m o l e s$
$1$ $m o l e$
So, $1$ $m o l e$ of $C l_{2}$ gas is evolved