Question

The total number of moles of valence electrons in 4.2g of $N_3{}^{-}$ ion are:

• A. $2.2N_A$
• B. $4.2N_A$
• C. $1.6N_A$
• D. $3.2N_A$

Answer 1

Answer: (C)

$1.6N_A$

Since $N_3^{-}$ has $16$ valence electron

$\therefore$ for $1$ mole $N_3^{-}\to (16valence{e}^{-}\times N_A)$

$\therefore 0.1mole{N}_3^{-}\to (16\times 0.1)N_A$

$\Rightarrow \underset{}{1.6N_A}$

Valence electron