Question

The total number of natural numbers lying between $20,000$ and $60,000$ including $60000,$ whose sum of digits is even is

• A. $40000$
• B. $20000$
• C. $5000$
• D. $25000$

Answer 1

The correct option is B $20000$

The no .of digits lying between $20,000$ and $60,000$ is $60,000-20,000=40,000$

Since The sum of digits are odd and even in a equal number

So the number of natural numbers having their sum of digits even is $40,000/2=20,000$