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Crystal Field Split in Octahedral Complexes

The total num...

Question

The total number of non-bonded electrons present in cyanamide ion is:

A

4

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B

2

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C

8

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D

0

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Solution

The correct option is C
8

$Cynamide ion= C N_{2}^{- 2} has Θ N = C = Θ N \leftrightarrow N C - N^{- 2} Total non bonded electrons=8$

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