Question

The total number of non-square natural numbers between ${16}^2$ and ${17}^2$ $=a\times b=c$. What is the value of $a$, $b$ and $c$ respectively?

• A. 2, 17, 34
• B. 2,16, 32
• C. 2,15,30
• D. None of these

Answer 1

The correct option is B

2,16, 32

Non-square nos. between $n^2$ and $(n+1{)}^2$ = $2n$

∴ Between ${16}^2$ and ${17}^2$ $=2\times 16=32$

a $\times$ b $=c$

So, a, b and c are 2, 16 and 32 respectively.