The correct option is A 2240
Let the number be abcd, where a,b,c and d are the digits.
The digit d can take 5 values. (1,3,5,7 and 9).
The digit 'a' can take any digit from 1 to 9 (it cannot take zero because it won't be a 4 digit number then). However, the value of a cannot be the same as that of d. Thus, we can have 8 possible values for the digit 'a'.
The digit b can be 0 as well. However, it cannot be the same as a or d. Hence, we can have 8 possible values for the digit 'b'.
Similarly, we can have 7 possible values for the digit 'c'
Thus, the number of four digit numbers which satisfy the above condition = 8×8×7×5=2240