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Question


The total number of optically active compounds formed in the following reaction is?
870101_5c61b2be9332439eaa454992622c9344.png

A
Zero
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B
Six
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C
Four
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D
Two
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Solution

The correct option is D Four
The total number of optically active compounds formed is four. The product has two chiral C atoms (marked with asterik). Thus, it has 2n=22=4 stereoisomers.
808608_870101_ans_a921b899b22044b4b41c715f193ae9ca.png

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