The total number of optically active isomer for ${C H}_{2} O H {(C H O H)}_{3} C H O$ is :

2

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4

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8

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12

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Solution

The correct option is D $8$
Total no. of chiral atoms are $3$
So, the total number of optically active isomer = $2^{n} = 2^{3} = 8$

Therefore, the correct option is $C$

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Similar questions

The total number of optically active isomers for $C H_{2} O H (C H O H)_{3} C H O$ are:

{C H}_{3} C H B r C H B r C O O H

C H_{3} C H (O H) C O O H

2, 3 -

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