Question

The total number of pi-bonds in $C{H}_2=CH-CH=CH-C\equiv CH$ are ______.

• A. two
• B. three
• C. four
• D. five

Answer 1

The correct option is C four

$$\begin{array}{ccc}\text{Nature of bond}& \text{Number of sigma bonds}& \text{Number of pi-bonds}\\ \text{Single bond}& \text{1}& \text{0}\\ \text{Double bond}& \text{1}& \text{1}\\ \text{Triple bond}& \text{1}& \text{2}\end{array}$$In the compound $C{H}_2=CH-CH=CH-C\equiv CH$, there are (2$\times$1) + (1$\times$2) = 4 pi-bonds in total.