Question

The total number of possible coordination isomers of the complex compound $\left[Cu{\left(N{H}_3\right)}_4\right]\left[PtC{l}_4\right]$ are:

• A. 3
• B. 6
• C. 2
• D. 4

Answer 1

The correct option is D 4

The total number of possible isomers of the complex compound $\left[Cu{\left(N{H}_3\right)}_4\right]\left[PtC{l}_4\right]$ are 4.

$\left[Cu{\left(N{H}_3\right)}_4\right]\left[PtC{l}_4\right]$

$\left[Cu{\left(N{H}_3\right)}_{3}Cl\right]\left[Pt\left(N{H}_3\right)C{l}_3\right]$

$\left[Pt{\left(N{H}_3\right)}_{3}Cl\right]\left[Cu\left(N{H}_3\right)C{l}_3\right]$

$\left[Pt\right(N{H}_3{)}_4]\left[Cu{\left(Cl\right)}_4\right]$

Option D is correct.