The total number of possible isomers for squar-planar $[P t (C l) {(N O}_{2} (N O_{3} {S C N)]}^{2 -}$ is:

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Solution

The correct option is B 12
This complex is of the form Mabcd which has the following isomers
But carefully observing the complex
Im $S \cdot C \equiv ¨ N$ both S and n can donate lp
Im $N O_{2}$ both N and O can donate lp
Thus, the total number of isomers will be $(2 \times 2) \times 3 = 12$
due to $S \cdot C \equiv N :$ duce to $N O_{2}$

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