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Question

The total number of possible isomers, for the complex [CuII(NH3)4][PtIICl4] is

A
6
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B
5
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C
4
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D
3
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Solution

The correct option is C 4
[Cu(NH3)3Cl][PtCl3NH3]
[Cu(NH3)2Cl2][PtCl2(NH3)2]
[Cu(NH3)4Cl3][PtCl4(NH3)3]
[CuCl4][Pt(NH3)4]

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