Question

The total number of possible isomers of the complex
$\left[Cu\right(N{H}_3{)}_4\left]\right[PtC{l}_4]$ is:

• A. 3
• B. 6
• C. 5
• D. 4

Answer 1

The correct option is D 4

For $\left[Cu\right(N{H}_3{)}_4\left]\right[PtC{l}_4]$ four isomers are possible.
Which are
(i) $\left[Cu\right(N{H}_3{)}_{3}Cl\left]\right[PtC{l}_3\left(N{H}_3\right)]$
(ii) $\left[Cu\right(N{H}_3{)}_{2}C{l}_2\left]\right[PtC{l}_2\left(N{H}_3{)}_2\right]$
(iii) $\left[Cu\right(N{H}_3\left)C{l}_3\right]\left[PtCl\right(N{H}_3{)}_3]$
(iv) $\left[CuC{l}_4\right]\left[Pt\right(N{H}_3{)}_4]$