Question

The total number of protons in $10$ g of calcium carbonate is:

$(N_0=6.023\times {10}^{23})$

• A. $1.505\times {10}^{24}$
• B. $2.047\times {10}^{23}$
• C. $3.011\times {10}^{24}$
• D. $4.095\times {10}^{24}$

Answer 1

The correct option is C $3.011\times {10}^{24}$

Mole of $CaC{O}_3=\frac{10}{100}=\frac{1}{10}mol$
Number of molecules of $CaC{O}_3=\frac{1}{10}\times N_A$

Number of protons in one molecule of $CaC{O}_3=20+6+3\times 8=50$

Total number of protons $=50\times \frac{1}{10}\times N_A=3.011\times {10}^{24}$ protons