The total number of protons present in 124 g of NO 3-are-A- 62 N AB- 124 N AC- 62 N AD- 31 N A

The correct option is A 62 N_AProtons in NO^ _3 = 31 nbsp; Moles of NO^ _3 = 12462 = 2 mole 1 mole NO^ _3 = 31 N_A protons 2 mole NO^ _3 = 62 N_A nbsp; ...

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Standard XII

Chemistry

Positive Rays and Neutrons

The total num...

Question

The total number of protons present in 124 g of $N O_{3}^{-}$ are:

124 N_{A}

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62 N_{A}

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31 N_{A}

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62 N_{A}

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Solution

The correct option is B $62 N_{A}$
Protons in $N O_{3}^{-} = 31$
Moles of $N O_{3}^{-} = \frac{124}{62} = 2$ mole
1 mole $N O_{3}^{-} = 31 N_{A}$ protons
2 mole $N O_{3}^{-} = 62 N_{A}$

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The total number of protons present in 124 g of NO−3 are:

The correct option is B 62 NAProtons in NO−3=31 Moles of NO−3=12462=2 mole 1 mole NO−3=31 NA protons 2 mole NO−3=62 NA

The total number of protons present in 124 g of $N O_{3}^{-}$ are:

The correct option is B $62 N_{A}$
Protons in $N O_{3}^{-} = 31$
Moles of $N O_{3}^{-} = \frac{124}{62} = 2$ mole
1 mole $N O_{3}^{-} = 31 N_{A}$ protons
2 mole $N O_{3}^{-} = 62 N_{A}$