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Question

The total number of protons present in 124 g of NO−3 are:

A
124 NA
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B
62 NA
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C
31 NA
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D
62 NA
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Solution

The correct option is B 62 NA
Protons in NO3=31
Moles of NO3=12462=2 mole
1 mole NO3=31 NA protons
2 mole NO3=62 NA

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