Question

The total number of rational terms in the expansion of ${(7^{\frac{1}{3}}+{11}^{\frac{1}{9}})}^{6561}$ is

• A. $731$
• B. $729$
• C. $728$
• D. $730$
• E. $732$

Answer 1

Answer: (D)

$730$

Total number of rational terms will be
$1+\frac{6561}{L.C.M(3,9)}$
$=1+\frac{6561}{9}$
$=729+1$
$=730$