The correct option is A 3
The total number of selections of at most n things from (2n+1) different things i.e. selecting 1,2,3,......n things from (2n+1) things
⟹ 2n+1C1+2n+1C2+2n+1C3+............................2n+1Cn
⟹ 12(2n+1C1+2n+1C2+2n+1C3+............................2n+1C2n)
⟹ 12(2n+1C0+2n+1C1+2n+1C2+2n+1C3+............................2n+1C2n+2n+1C2n+1)-1
⟹12(22n+1)-1
⟹22n−1=63
⟹22n=26
⇒n=3