The total number of - and - bonds present in azobenzene are-

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The total num...

Question

The total number of $σ$ and $π$ bonds present in azobenzene are:

24 σ

6 π

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25 σ

7 π

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28 σ

6 π

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27 σ

6 π

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I = \int_{- π / 6}^{π / 6} \frac{π + 4 x^{5}}{1 - sin (| x | + π / 6)} d x,

I

f (x) = {sin}^{- 1} (sin x) \forall x \in [6 π, 7 π]

f (x)

(\frac{π}{6}, \frac{π}{3})

I_{1} = \int_{π / 6}^{π / 3} {sec}^{2} x f (2 sin 2 x) d x

I_{2} = \int_{π / 6}^{π / 3} c o {sec}^{2} x f (2 sin 2 x) d x,

\int_{π / 6}^{π / 3} \frac{1 d x}{1 + \sqrt{cot x}} = \frac{π}{2}

\int_{π / 6}^{π / 3} \frac{f (x) d x}{f (x) + f (\frac{π}{2} - x)} = \frac{π}{12}

\int_{π / 6}^{π / 4} cosec x d x

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