The total number of stereoisomers of 2,3-dibromobutane is:

2

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3

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4

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5

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Solution

The correct option is C $3$
Compound with even no. of chiral atoms and it can be divided into two equal halves
so, total no. of stereo isomers $= 2^{n - 1} + 2^{n / 2 - 1}$
$= 2^{1} + 2^{0} = 2 + 1 = 3$

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It is given that when (±)-2,3-dibromobutane reacts with $K O H$ , some of the products formed are:

Explain via mechanism and then choose the correct ones from the following.

Monosubstitution of (2S,3S)-2,3-dibromobutane using $O H^{-}$ yields a mixture of products.
Monosubstitution of (2S,3S)-2,3-dibromobutane using $O H^{-}$ yields a single major product.
Monosubstitution of (2R,3R)-2,3-dibromobutane using $O H^{-}$ yields a mixture of products.
Monosubstitution of (2S,3S)-2,3-dibromobutane using $O H^{-}$ yields a mixture of products.

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